python判断列表是否为空
(*-*)浩
2019-08-29 10:13:4011804浏览 · 0收藏 · 0评论
is not None 判断
列表不为空
list_1 = []
if list_1 is not None:
print('list is not none')列表为空
list_1 = []
if list_1[0] is None:
print('list_1 is none')if 列表判断
列表不为空（空列表等于 False）
list_2 = []
if list_2:
print('list_2 is not none')length列表长度判断
列表为空
list_3 = []
if len(list_3) == 0:
print('list_3 is none')list_3 = []
if len(list):
print('list_3 is not none') 
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